Neopentyl bromide undergoes dehydro halogenation to give alkene even though it has no β text- hydrogen. This is due to

Question

Neopentyl bromide undergoes dehydro halogenation to give alkene even though it has no β text- hydrogen. This is due to (A) E2 mechanism (B) E1 mechanism (C) due to rearrangement of carbocation by E1 mechanism (D) E1 CB mechanism

Tardigrade Admin · Accepted Answer

Neopentyl bromide undergoes dehydro-halogenation to give alkene even though it has no β text- hydrogen atom. This is due to rearrangement of carbocation by E1 mechanism. CH3- undersetCH3 oversetCH3 mathop underset mathbf| overset mathbf| mathopC -CH2Br xrightarrow[-Br-]

Q. Neopentyl bromide undergoes dehydro halogenation to give alkene even though it has no $β -$ hydrogen. This is due to

E2 mechanism

E1 mechanism

due to rearrangement of carbocation by E1 mechanism

E1 CB mechanism

Neopentyl bromide undergoes dehydro-halogenation to give alkene even though it has no $β -$ hydrogen atom. This is due to rearrangement of carbocation by $E_{1}$ mechanism. $C H_{3} - C H_{3} ∣ C ∣ C H_{3} - C H_{2} B r - B r^{-}$

Q. Neopentyl bromide undergoes dehydro halogenation to give alkene even though it has no β- hydrogen. This is due to