Q. $N d^{2 +} =$

1024 272 JEE MainJEE Main 2023The p-Block Elements - Part2 Report Error

A

$4 f^{3}$

0%

B

$4 f^{4} 6 s^{2}$

0%

C

$4 f^{2} 6 s^{2}$

0%

D

$4 f^{4}$

100%

Solution:

$N d (60) = [X e] 4 f^{4} 5 d^{0} 6 s^{2}$
$N d^{2 +} = [X e] 4 f^{4} 5 d^{0} 5 s^{0}$