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Chemistry
Nd 2+=
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Q. $Nd ^{2+}=$
JEE Main
JEE Main 2023
The p-Block Elements - Part2
A
$4 f ^3$
0%
B
$4 f^4 6 s^2$
0%
C
$4 f ^2 6 s ^2$
0%
D
$4 f ^4$
100%
Solution:
$ Nd (60)=[ Xe ] 4 f ^4 5 d ^0 6 s ^2 $
$ Nd ^{2+}=[ Xe ] 4 f ^4 5 d ^0 5 s ^0$