Natural length of a spring is 60 cm and its spring constant is 4000 N / m. A mass of 20 kg is hung from it. The extension produced in the spring is (. take .g=9.8 m / s 2) :

Question

Natural length of a spring is 60 cm and its spring constant is 4000 N / m. A mass of 20 kg is hung from it. The extension produced in the spring is (. take .g=9.8 m / s 2) : (A) 4.9 cm (B) 0.49 cm (C) 9.4 cm (D) 0.94 cm

Tardigrade Admin · Accepted Answer

Given, 1=60 cm =60 × 10-2 m m =20 kg , k =4000 N / m The weight hung from the spring = mg =20 × 9.8=196 N Let x be the extension produced in spring. Now, force applied by the spring = downward force on the spring ∴ kx = mg ⇒ x =( mg / k ) or, x=(20 × 9.8/4000) =0.049 m =4.9 cm

Q. Natural length of a spring is 60cm and its spring constant is 4000N/m. A mass of 20kg is hung from it. The extension produced in the spring is ( take g=9.8m/s2) :

4.9 cm

0.49 cm

9.4 cm

0.94 cm

Given, 1=60cm=60×10−2m m=20kg, k=4000N/m The weight hung from the spring =mg=20×9.8=196N Let x be the extension produced in spring. Now, force applied by the spring = downward force on the spring ∴kx=mg ⇒x=kmg​ or, x=400020×9.8​ =0.049m=4.9cm

Q. Natural length of a spring is $60 c m$ and its spring constant is $4000 N / m$ . A mass of $20 k g$ is hung from it. The extension produced in the spring is $($ take $g = 9.8 m / s^{2})$ :