Na2CrO4 xrightarrowA Na2SO4 + underset textOrangeB arrow underset textOrange RedC + NaCl A, B and C respectively are:

Question

Na2CrO4 xrightarrowA Na2SO4 + underset textOrangeB arrow underset textOrange RedC + NaCl A, B and C respectively are: (A) K2SO4, K2CrO4 and K2Cr2O7 (B) K2SO4, Na2CrO4 and Na2Cr2O7 (C) H2SO4, NaCrO2 and K2Cr2O7 (D) H2SO4, Na2Cr2O7 and K2Cr2O7

Tardigrade Admin · Accepted Answer

This reaction is the method of preparation of

K_{2} C r_{2} O_{7}

2 N a_{2} C r O_{4} + H_{2} S O_{4} \to Sodium dichromate (orange) N a_{2} C r_{2} O_{7} + N a_{2} S O_{4} + H_{2} S O_{4}

2 N a_{2} C r_{2} O_{7} + 2 K Cl \to (orange red) Potassium dichromate K_{2} C r_{2} O_{7} + 2 N a Cl

Q. $N a_{2} C r O_{4} A N a_{2} S O_{4} + Orange B \to Orange Red C + N a Cl$
A, B and C respectively are:

$K_{2} S O_{4}, K_{2} C r O_{4}$ and $K_{2} C r_{2} O_{7}$

$K_{2} S O_{4}, N a_{2} C r O_{4}$ and $N a_{2} C r_{2} O_{7}$

$H_{2} S O_{4}, N a C r O_{2}$ and $K_{2} C r_{2} O_{7}$

$H_{2} S O_{4}, N a_{2} C r_{2} O_{7}$ and $K_{2} C r_{2} O_{7}$

This reaction is the method of preparation of $K_{2} C r_{2} O_{7}$
$2 N a_{2} C r O_{4} + H_{2} S O_{4} \to Sodium dichromate (orange) N a_{2} C r_{2} O_{7} + N a_{2} S O_{4} + H_{2} S O_{4}$
$2 N a_{2} C r_{2} O_{7} + 2 K Cl \to (orange red) Potassium dichromate K_{2} C r_{2} O_{7} + 2 N a Cl$

Q. Na2​CrO4​A​Na2​SO4​+OrangeB​→Orange RedC​+NaCl A, B and C respectively are:

K2​SO4​,K2​CrO4​ and K2​Cr2​O7​

K2​SO4​,Na2​CrO4​ and Na2​Cr2​O7​

H2​SO4​,NaCrO2​ and K2​Cr2​O7​

H2​SO4​,Na2​Cr2​O7​ and K2​Cr2​O7​