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Tardigrade
Question
Chemistry
(Na)2S+(Na)2[Fe (CN)5 NO] arrow (Na)4[Fe (CN)5 NOS] Find sum of oxidation number of Fe in reactant (complex) and product (complex) are.
Q.
(
N
a
)
2
S
+
(
N
a
)
2
[
F
e
(
CN
)
5
NO
]
→
(
N
a
)
4
[
F
e
(
CN
)
5
NOS
]
Find sum of oxidation number of
F
e
in reactant (complex) and product (complex) are.
221
185
NTA Abhyas
NTA Abhyas 2022
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Answer:
4
Solution:
..