n-propyl bromide on treatment with ethanolic potassium hydroxide produces

Question

n-propyl bromide on treatment with ethanolic potassium hydroxide produces (A) propane (B) propene (C) propyne (D) propanol

Tardigrade Admin · Accepted Answer

An alkyl halide containing at least one β-H, on treatment with ethanolic KOH, undergoes dehydrohalogenation, giving alkene. CH3 -CH2-CH2 -Br+KOH xrightarrow textEthanol CH3-CH =CH2

Q. n-propyl bromide on treatment with ethanolic potassium hydroxide produces

propane

propene

propyne

propanol

An alkyl halide containing at least one $β - H$ , on treatment with ethanolic $K O H$ , undergoes dehydrohalogenation, giving alkene.
$C H_{3} - C H_{2} - C H_{2} - B r + K O H Ethanol C H_{3} - C H = C H_{2}$

Q. n-propyl bromide on treatment with ethanolic potassium hydroxide produces

propane

propene

propyne

propanol

An alkyl halide containing at least one β−H, on treatment with ethanolic KOH, undergoes dehydrohalogenation, giving alkene. CH3​−CH2​−CH2​−Br+KOHEthanol​CH3​−CH=CH2​

An alkyl halide containing at least one $β - H$ , on treatment with ethanolic $K O H$ , undergoes dehydrohalogenation, giving alkene.
$C H_{3} - C H_{2} - C H_{2} - B r + K O H Ethanol C H_{3} - C H = C H_{2}$