n-Propyl benzene can be obtained in quantitative yield by following method: (i) By treating benzene with n-propyl chloride in presence of AlCl3 (ii) By treating excess of benzene with n-propyl chloride in presence of AlCl3 (iii) By treating benzene with allyl chloride in presence of AlCl3 followed by reduction (iv) By treating benzene with propionyl chloride in the presence of AlCl3 followed by Clemmensen reduction.

Question

n-Propyl benzene can be obtained in quantitative yield by following method: (i) By treating benzene with n-propyl chloride in presence of AlCl3 (ii) By treating excess of benzene with n-propyl chloride in presence of AlCl3 (iii) By treating benzene with allyl chloride in presence of AlCl3 followed by reduction (iv) By treating benzene with propionyl chloride in the presence of AlCl3 followed by Clemmensen reduction. (A) By (ii), (iii) and (iv) (B) By (i), (iii) and (iv) (C) By (iii) and (iv) (D) By (ii) only

Tardigrade Admin · Accepted Answer

(i) and (ii) methods will form isopropyl benzene because n-propyl carbocation, being less stable, rearranges to the more stable (2°) isopropyl carbocation. Moreover, method (i) will lead to polyalkylation. Methods (iii) and (iv) can be used for preparing n-propyl benzene. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/61801791c20d928b46b9380ec69989f8-.png" />

By $(ii), (iii)$ and $(i v)$

By $(i), (iii)$ and $(i v)$

By $(iii)$ and $(i v)$

By $(ii)$ only

$(i)$ and $(ii)$ methods will form isopropyl benzene because $n$ -propyl carbocation, being less stable, rearranges to the more stable $(2°)$ isopropyl carbocation. Moreover, method $(i)$ will lead to polyalkylation. Methods $(iii)$ and $(i v)$ can be used for preparing $n$ -propyl benzene.

By (ii),(iii) and (iv)

By (i),(iii) and (iv)

By (iii) and (iv)

By (ii) only

(i) and (ii) methods will form isopropyl benzene because n-propyl carbocation, being less stable, rearranges to the more stable (2°) isopropyl carbocation. Moreover, method (i) will lead to polyalkylation. Methods (iii) and (iv) can be used for preparing n-propyl benzene.

By $(ii), (iii)$ and $(i v)$

By $(i), (iii)$ and $(i v)$

By $(iii)$ and $(i v)$

By $(ii)$ only

$(i)$ and $(ii)$ methods will form isopropyl benzene because $n$ -propyl carbocation, being less stable, rearranges to the more stable $(2°)$ isopropyl carbocation. Moreover, method $(i)$ will lead to polyalkylation. Methods $(iii)$ and $(i v)$ can be used for preparing $n$ -propyl benzene.