n identical cells, each of emf ε and internal resistance r, are joined in series to form a closed circuit. The potential difference across any one cell is

Question

n identical cells, each of emf ε and internal resistance r, are joined in series to form a closed circuit. The potential difference across any one cell is (A) zero (B) ε (C) (ε/n) (D) (n-1/n) ε

Tardigrade Admin · Accepted Answer

Current in circuit, is i=(n ε/n r)=(ε/r) <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/91aef0201d42893669dad667b504ca1a-.png" /> The equivalent circuit of one cell is shown in figure. The potential difference across the cell is VA-VB=-ε+i r=-ε+(ε/r) r=0

Q. $n$ identical cells, each of emf $ε$ and internal resistance $r$ , are joined in series to form a closed circuit. The potential difference across any one cell is

zero

$ε$

$\frac{ε}{n}$

$\frac{n - 1}{n} ε$

Current in circuit, is $i = \frac{n ε}{n r} = \frac{ε}{r}$

The equivalent circuit of one cell is shown in figure.
The potential difference across the cell is
$V_{A} - V_{B} = - ε + i r = - ε + \frac{ε}{r} r = 0$

Q. n identical cells, each of emf ε and internal resistance r, are joined in series to form a closed circuit. The potential difference across any one cell is

zero

ε

nε​

nn−1​ε

Current in circuit, is i=nrnε​=rε​ The equivalent circuit of one cell is shown in figure. The potential difference across the cell is VA​−VB​=−ε+ir=−ε+rε​r=0

Q. $n$ identical cells, each of emf $ε$ and internal resistance $r$ , are joined in series to form a closed circuit. The potential difference across any one cell is

$ε$

$\frac{ε}{n}$

$\frac{n - 1}{n} ε$

Current in circuit, is $i = \frac{n ε}{n r} = \frac{ε}{r}$

The equivalent circuit of one cell is shown in figure.
The potential difference across the cell is
$V_{A} - V_{B} = - ε + i r = - ε + \frac{ε}{r} r = 0$