MX2 dissociates into M2+ and X- ions in an aqueous solution, with a degree of dissociation α of 0.5. The ratio of the observed depression of freezing point of the aqueous solution to the value of the depression of freezing point in the absence of ionic dissociation is

Question

MX2 dissociates into M2+ and X- ions in an aqueous solution, with a degree of dissociation α of 0.5. The ratio of the observed depression of freezing point of the aqueous solution to the value of the depression of freezing point in the absence of ionic dissociation is (A) 5 (B) 3 (C) 2 (D) 1

Tardigrade Admin · Accepted Answer

underset(1 -α)MX2 leftharpoons undersetαMa2+ + underset2 α2X- i = 1 - α + α + 2α i = 1 + 2α (∵ α = 0.5) i = 1 + 2 × 0.5 = 2

Q. $M X_{2}$ dissociates into $M^{2^{+}}$ and $X^{-}$ ions in an aqueous solution, with a degree of dissociation $α$ of $0.5$ . The ratio of the observed depression of freezing point of the aqueous solution to the value of the depression of freezing point in the absence of ionic dissociation is

$5$

$3$

$2$

$1$

$(1 - α) M X_{2} ⇌ α M a^{2 +} + 2 α 2 X^{-}$
$i = 1 - α + α + 2 α$
$i = 1 + 2 α (∵ α = 0.5)$
$i = 1 + 2 \times 0.5 = 2$

Q. MX2​ dissociates into M2+ and X− ions in an aqueous solution, with a degree of dissociation α of 0.5. The ratio of the observed depression of freezing point of the aqueous solution to the value of the depression of freezing point in the absence of ionic dissociation is

5

3

2

1

(1−α)MX2​​⇌αMa2+​+2α2X−​ i=1−α+α+2α i=1+2α(∵α=0.5) i=1+2×0.5=2

Q. $M X_{2}$ dissociates into $M^{2^{+}}$ and $X^{-}$ ions in an aqueous solution, with a degree of dissociation $α$ of $0.5$ . The ratio of the observed depression of freezing point of the aqueous solution to the value of the depression of freezing point in the absence of ionic dissociation is

$5$

$3$

$2$

$1$

$(1 - α) M X_{2} ⇌ α M a^{2 +} + 2 α 2 X^{-}$
$i = 1 - α + α + 2 α$
$i = 1 + 2 α (∵ α = 0.5)$
$i = 1 + 2 \times 0.5 = 2$