Molecular weight of oxygen is 32 amu . At STP , volume of 1 gm of oxygen is 700 cm3 . What is the value of gas constant R ?

Question

Molecular weight of oxygen is 32 amu . At STP , volume of 1 gm of oxygen is 700 cm3 . What is the value of gas constant R ? (A)  18.23 J mol-1 K-1  (B)  27.73 J mol-1 K-1  (C)  37.97 J mol-1 K-1  (D)  8.31 J mol-1 K-1

Tardigrade Admin · Accepted Answer

PV=nRT At STP, P=105, T=273, n=(1/32), V=700×10-6m R=(PV/nT) =(105×700×10-6/1 32×273) ≃ 8.31 J mol-1 K-1

Q. Molecular weight of oxygen is $32 am u$ . At $STP$ , volume of $1 g m$ of oxygen is $700 c m^{3}$ . What is the value of gas constant $R$ ?

$18.23 J m o l^{- 1} K^{- 1}$

$27.73 J m o l^{- 1} K^{- 1}$

$37.97 J m o l^{- 1} K^{- 1}$

$8.31 J m o l^{- 1} K^{- 1}$

$P V = n RT$
At $STP$ , $P = 1 0^{5}$ ,
$T = 273$ ,
$n = \frac{1}{32}$ ,
$V = 700 \times 1 0^{- 6} m$
$R = \frac{P V}{n T}$
$= \frac{1 0 ^{5} \times 700 \times 1 0 ^{- 6}}{132 \times 273}$
$≃ 8.31 J m o l^{- 1} K^{- 1}$

Q. Molecular weight of oxygen is 32amu . At STP , volume of 1gm of oxygen is 700cm3 . What is the value of gas constant R ?

18.23Jmol−1K−1

27.73Jmol−1K−1

37.97Jmol−1K−1

8.31Jmol−1K−1