Mole fraction of toluene in the vapor which is in equilibrium with a solution containing benzene and toluene having 2 mol each is Given: Saturation vapor pressure of benzene =120 torr Saturation vapor pressure of toluene =80 torr

Question

Mole fraction of toluene in the vapor which is in equilibrium with a solution containing benzene and toluene having 2 mol each is Given: Saturation vapor pressure of benzene =120 torr Saturation vapor pressure of toluene =80 torr (A) 0.5 (B) 0.25 (C) 0.6 (D) 0.4

Tardigrade Admin · Accepted Answer

Total vapor pressure =(1/2) × 120+(1/2) × 80=100 torr yA × 100=xA pA° as per Raoult's law or yt=(1/2) × (80/100)=0.4

Q. Mole fraction of toluene in the vapor which is in equilibrium with a solution containing benzene and toluene having $2$ mol each is
Given: Saturation vapor pressure of benzene $= 120$ torr
Saturation vapor pressure of toluene $= 80$ torr

0.5

0.25

0.6

0.4

Total vapor pressure $= \frac{1}{2} \times 120 + \frac{1}{2} \times 80 = 100$ torr

$y_{A} \times 100 = x_{A} p_{A}^{\circ}$ as per Raoult's law

or $y_{t} = \frac{1}{2} \times \frac{80}{100} = 0.4$

Q. Mole fraction of toluene in the vapor which is in equilibrium with a solution containing benzene and toluene having 2 mol each is Given: Saturation vapor pressure of benzene =120 torr Saturation vapor pressure of toluene =80 torr

0.5

0.25

0.6

0.4

Total vapor pressure =21​×120+21​×80=100 torr yA​×100=xA​pA∘​ as per Raoult's law or yt​=21​×10080​=0.4

Q. Mole fraction of toluene in the vapor which is in equilibrium with a solution containing benzene and toluene having $2$ mol each is
Given: Saturation vapor pressure of benzene $= 120$ torr
Saturation vapor pressure of toluene $= 80$ torr

Total vapor pressure $= \frac{1}{2} \times 120 + \frac{1}{2} \times 80 = 100$ torr

$y_{A} \times 100 = x_{A} p_{A}^{\circ}$ as per Raoult's law

or $y_{t} = \frac{1}{2} \times \frac{80}{100} = 0.4$