Question

Mole fraction of $C_3{H}_5(OH{)}_3$ in a solution of 36 g of water and 46 g of glycerine is:

• A. $0.46$
• B. $0.36$
• C. $0.20$
• D. $0.40$

Answer 1

Answer: (C)

Mole of $H_{2}O=\frac{36}{18}=2$
Mole of glycerine $=\frac{46}{92}=0.5$
Total moles $=2+0.5=2.5$
Mole fractions of glycerine $=\frac{n_1}{n_1+n_2}=\frac{0.5}{2.5}$
$=0.2$