Question

Mole fraction of a solute in an aqueous solution is $0.2$. The molality of the solution will be

• A. $13.88$
• B. $1.388$
• C. $0.138$
• D. $0.0138$

Answer 1

Answer: (A)

${\chi }_B=0.2,{\chi }_A=0.1$
$m=\frac{{\chi }_B\times 1000}{{\chi }_A\times M{w}_A}=\frac{0.2\times 1000}{0.8\times 18}=13.88$