Molarity and molality of a solution of caustic soda are respectively 11.12 M and 94.12 m. The density of the solution is

Question

Molarity and molality of a solution of caustic soda are respectively 11.12 M and 94.12 m. The density of the solution is (A) 0.556 g mL-1 (B) 5.56 g mL-1 (C) 55.6 g mL-1 (D) none of these

Tardigrade Admin · Accepted Answer

d=M ((1/m)+( textmolar mass of solute/1000)) d=11.12((1/94.12)+(40/1000)) =0.556 g ml-1

Q. Molarity and molality of a solution of caustic soda are respectively 11.12 M and 94.12 m. The density of the solution is

$0.556 g m L^{- 1}$

$5.56 g m L^{- 1}$

$55.6 g m L^{- 1}$

none of these

$d = M (\frac{1}{m} + \frac{molar mass of solute}{1000})$
$d = 11.12 (\frac{1}{94.12} + \frac{40}{1000})$
$= 0.556 g m l^{- 1}$

Q. Molarity and molality of a solution of caustic soda are respectively 11.12 M and 94.12 m. The density of the solution is

0.556gmL−1

5.56gmL−1

55.6gmL−1

none of these

d=M(m1​+1000molar mass of solute​) d=11.12(94.121​+100040​) =0.556gml−1

$0.556 g m L^{- 1}$

$5.56 g m L^{- 1}$

$55.6 g m L^{- 1}$

$d = M (\frac{1}{m} + \frac{molar mass of solute}{1000})$
$d = 11.12 (\frac{1}{94.12} + \frac{40}{1000})$
$= 0.556 g m l^{- 1}$