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J & K CETJ & K CET 2004States of Matter
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Solution:
PV=nRT Here n=1V=PRT
At NTPV=1R×273=273R
At 0∘C(273K) and 2atmV =2R×273=2273R
At 127∘C(400K) and atmV=1R×400=400R
At 273∘C(546K) and 2atmV=2R×546=273R
Thus, molar volume is maximum at 127∘C and 1atm pressure