Molar solubility of helium, nitrogen and oxygen are plotted against partial pressure of the gas at constant temperature. Henry’s law constant for these gases will lie in following sequence?

Question

Molar solubility of helium, nitrogen and oxygen are plotted against partial pressure of the gas at constant temperature. Henry’s law constant for these gases will lie in following sequence? (A) O 2> N 2> He (B) O 2< N 2< He (C) O 2= N 2= He (D) O 2> N 2< He

Tardigrade Admin · Accepted Answer

Gas Temperature KH (K bar) He 293 144.97 N2 293 76.48 O2 293 34.86 Higher the value of Henry's Law constant, the lower is the solublity of the gas in the liquid.

Q. Molar solubility of helium, nitrogen and oxygen are plotted against partial pressure of the gas at constant temperature.
Henry’s law constant for these gases will lie in following sequence?

$O_{2} > N_{2} > He$

$O_{2} < N_{2} < He$

$O_{2} = N_{2} = He$

$O_{2} > N_{2} < He$

Gas Temperature $K_{H} (K ba r)$

He 293 144.97

$N_{2}$ 293 76.48

$O_{2}$ 293 34.86

Higher the value of Henry's Law constant, the lower is the solublity of the gas in the liquid.

Q. Molar solubility of helium, nitrogen and oxygen are plotted against partial pressure of the gas at constant temperature. Henry’s law constant for these gases will lie in following sequence?

O2​>N2​>He

O2​<N2​<He

O2​=N2​=He

O2​>N2​<He