Molar heat capacity at constant P for a substance is equal to

Question

Molar heat capacity at constant P for a substance is equal to (A) ( partial U / partial T ) v  (B) ( partial H / partial T ) v  (C) ( partial H / partial T ) v  (D) ( partial H / partial T ) p

Tardigrade Admin · Accepted Answer

Cp=(Qp/Δ T)=(Δ H/Δ T) or (( partial H/ partial T))p .

Q. Molar heat capacity at constant P for a substance is equal to

$(\partial U / \partial T)_{v}$

$(\partial H / \partial T)_{v}$

$(\partial H / \partial T)_{v}$

$(\partial H / \partial T)_{p}$

$C_{p} = \frac{Q _{p}}{Δ T} = \frac{Δ H}{Δ T}$
or $(\frac{\partial H}{\partial T})_{p}$ .

Q. Molar heat capacity at constant P for a substance is equal to

(∂U/∂T)v​

(∂H/∂T)v​

(∂H/∂T)v​

(∂H/∂T)p​

Cp​=ΔTQp​​=ΔTΔH​ or (∂T∂H​)p​ .

$(\partial U / \partial T)_{v}$

$(\partial H / \partial T)_{v}$

$(\partial H / \partial T)_{v}$

$(\partial H / \partial T)_{p}$

$C_{p} = \frac{Q _{p}}{Δ T} = \frac{Δ H}{Δ T}$
or $(\frac{\partial H}{\partial T})_{p}$ .