Molar conductivity of a solution of an electrolyte AB3 is 150 Scm2mol- 1 . If it ionizes as textAB3 arrow textA3 + + 3 textB- , its equivalent conductivity will be

Question

Molar conductivity of a solution of an electrolyte AB3 is 150 Scm2mol- 1 . If it ionizes as textAB3 arrow textA3 + + 3 textB- , its equivalent conductivity will be (A) 150(. in . Scm 2 eq -1) (B) 75(. in . Scm 2 eq -1) (C) 50(. in . Scm 2 eq -1) (D) 80(. in Scm 2 eq -1 )

Tardigrade Admin · Accepted Answer

∧ e q=[(1/n+ × Z+)]∧ m Where, ∧ m= molar conductance n+= number of cations Z+= charge of cation ∧ mathrmeq=((1/1 × 3)) × 150=50

Q. Molar conductivity of a solution of an electrolyte $A B_{3}$ is $150$ $S c m^{2} m o l^{- 1}$ . If it ionizes as $AB_{3} \to A^{3 +} + 3 B^{-}$ , its equivalent conductivity will be

$150 ($ in $S c m^{2} e q^{- 1})$

$75 ($ in $S c m^{2} e q^{- 1})$

$50 ($ in $S c m^{2} e q^{- 1})$

$80 ($ in $S c m^{2} e q^{- 1}$ )

$\land_{e q} = [\frac{1}{n ^{+} \times Z ^{+}}] \land_{m}$

Where, $\land_{m} =$ molar conductance

$n^{+} =$ number of cations

$Z^{+} =$ charge of cation

$\land_{eq} = (\frac{1}{1 \times 3}) \times 150 = 50$

Q. Molar conductivity of a solution of an electrolyte AB3​ is 150 Scm2mol−1 . If it ionizes as AB3​→A3++3B− , its equivalent conductivity will be

150( in Scm2eq−1)

75( in Scm2eq−1)

50( in Scm2eq−1)

80( in Scm2eq−1 )