Molal depression constant for water is 1.86°C The freezing point of a 0.05 molal solution of a non-electrolyte in water, is

Question

Molal depression constant for water is 1.86°C The freezing point of a 0.05 molal solution of a non-electrolyte in water, is (A)  -1.86°C  (B)  -0.93°C  (C)  -0.093°C (D)  0.93°C

Tardigrade Admin · Accepted Answer

Molal depression constant kf=1.86° C Molality =0.05 ⇒ Δ Tf=kf × molality Δ Tf=1.86 × 0.05 Δ Tf=0.093° C Δ Tf=T1-T2 where, T1= freezing point of solvent T2 = freezing point of solution T1=0° C 0.093=0-T2 T2=-0.093

Q. Molal depression constant for water is $1.8 6^{\circ} C$ The freezing point of a $0.05$ molal solution of a non-electrolyte in water, is

$- 1.8 6^{\circ} C$

$- 0.9 3^{\circ} C$

$- 0.09 3^{\circ} C$

$0.9 3^{\circ} C$

Q. Molal depression constant for water is 1.86∘C The freezing point of a 0.05 molal solution of a non-electrolyte in water, is

−1.86∘C

−0.93∘C

−0.093∘C

0.93∘C

Molal depression constant kf​=1.86∘C Molality =0.05 ⇒ ΔTf​=kf​× molality ΔTf​=1.86×0.05 ΔTf​=0.093∘C ΔTf​=T1​−T2​ where, T1​= freezing point of solvent T2​ = freezing point of solution T1​=0∘C 0.093=0−T2​T2​=−0.093

Q. Molal depression constant for water is $1.8 6^{\circ} C$ The freezing point of a $0.05$ molal solution of a non-electrolyte in water, is

$- 1.8 6^{\circ} C$

$- 0.9 3^{\circ} C$

$- 0.09 3^{\circ} C$

$0.9 3^{\circ} C$