Mol fraction of the component A in vapour phase is x1 and mol fraction of component A in liquid phase is x2 (If pA°= vapour pressure of pure A ; pB°= vapour pressure of pure B ), then total vapour pressure of the liquid mixture is:

Question

Mol fraction of the component A in vapour phase is x1 and mol fraction of component A in liquid phase is x2 (If pA°= vapour pressure of pure A ; pB°= vapour pressure of pure B ), then total vapour pressure of the liquid mixture is: (A) (pA° x2/x1) (B) (pA° x1/x2) (C) (pB° x1/x2) (D) (pB° x2/x1)

Tardigrade Admin · Accepted Answer

p A = p A ° ⋅ x 2 p B = p B °=(1- x 2) p text Total= p A ° ⋅ x 2+ p B °(1- x 2)...(i) Also x1=(pA/pA+pB)=(pA/pA° x2+pB°(1-x2)) or p A ° ⋅ x 2+ p B °(1- x 2)=( p A / x 1) Put in (i) p text Total =(pA/x1)=(pA° x2/x1)

Q. Mol fraction of the component $A$ in vapour phase is $x_{1}$ and mol fraction of component $A$ in liquid phase is $x_{2}$ (If $p_{A}^{\circ} =$ vapour pressure of pure $A; p_{B}^{\circ} =$ vapour pressure of pure $B$ ), then total vapour pressure of the liquid mixture is:

$\frac{p _{A}^{\circ} x _{2}}{x _{1}}$

$\frac{p _{A}^{\circ} x _{1}}{x _{2}}$

$\frac{p _{B}^{\circ} x _{1}}{x _{2}}$

$\frac{p _{B}^{\circ} x _{2}}{x _{1}}$

Q. Mol fraction of the component A in vapour phase is x1​ and mol fraction of component A in liquid phase is x2​ (If pA∘​= vapour pressure of pure A;pB∘​= vapour pressure of pure B ), then total vapour pressure of the liquid mixture is:

x1​pA∘​x2​​

x2​pA∘​x1​​

x2​pB∘​x1​​

x1​pB∘​x2​​

pA​=pA∘​⋅x2​pB​=pB∘​=(1−x2​) pTotal​=pA∘​⋅x2​+pB∘​(1−x2​)...(i) Also x1​=pA​+pB​pA​​=pA∘​x2​+pB∘​(1−x2​)pA​​ or pA∘​⋅x2​+pB∘​(1−x2​)=x1​pA​​ Put in (i) pTotal ​=x1​pA​​=x1​pA∘​x2​​

Q. Mol fraction of the component $A$ in vapour phase is $x_{1}$ and mol fraction of component $A$ in liquid phase is $x_{2}$ (If $p_{A}^{\circ} =$ vapour pressure of pure $A; p_{B}^{\circ} =$ vapour pressure of pure $B$ ), then total vapour pressure of the liquid mixture is:

$\frac{p _{A}^{\circ} x _{2}}{x _{1}}$

$\frac{p _{A}^{\circ} x _{1}}{x _{2}}$

$\frac{p _{B}^{\circ} x _{1}}{x _{2}}$

$\frac{p _{B}^{\circ} x _{2}}{x _{1}}$