MnO-4 is of intense pink colour, though Mn is in (+7) oxidation state. It is due to

Question

MnO-4 is of intense pink colour, though Mn is in (+7) oxidation state. It is due to (A) oxygen gives colour to it (B) None of the above is correct (C) charge transfer when Mn gives its electron to oxygen (D) character transfer when oxygen gives its electron to Mn making it Mn (+VI) and hence coloured

Tardigrade Admin · Accepted Answer

This is called ligand to metal charge transfer phenomenon

Q. $M n O_{4}^{-}$ is of intense pink colour, though $M n$ is in $(+ 7)$ oxidation state. It is due to

oxygen gives colour to it

None of the above is correct

charge transfer when $M n$ gives its electron to oxygen

character transfer when oxygen gives its electron to $M n$ making it $M n (+ V I)$ and hence coloured

This is called ligand to metal charge transfer phenomenon

Q. MnO4−​ is of intense pink colour, though Mn is in (+7) oxidation state. It is due to

oxygen gives colour to it

None of the above is correct

charge transfer when Mn gives its electron to oxygen

character transfer when oxygen gives its electron to Mn making it Mn(+VI) and hence coloured

This is called ligand to metal charge transfer phenomenon

Q. $M n O_{4}^{-}$ is of intense pink colour, though $M n$ is in $(+ 7)$ oxidation state. It is due to

charge transfer when $M n$ gives its electron to oxygen

character transfer when oxygen gives its electron to $M n$ making it $M n (+ V I)$ and hence coloured