MnO2-4 (1 mole) in neutral aqueous medium is disproportionate to

Question

MnO2-4 (1 mole) in neutral aqueous medium is disproportionate to (A) 2/3mole of MnO-4 and 1/3 mole of MnO2 (B) 1/3mole of MnO-4 and 2/3 mole of Mn O2 (C) 1/3mole of Mn2O-4 and 1/3 mole of Mn O2 (D) 2/3mole of Mn2O-4 and 1/3 mole of MnO2

Tardigrade Admin · Accepted Answer

MnO42- in neutral aqueous medium is disproportionate to (2/3) mole of MnO-4 and (1 /3) mole of MnO2.

Q. $M n O_{4}^{2 -}$ (1 mole) in neutral aqueous medium is disproportionate to

$2/3$ mole of $M n O_{4}^{-}$ and $1/3$ mole of $M n O_{2}$

$1/3$ mole of $M n O_{4}^{-}$ and $2/3$ mole of $M n O_{2}$

$1/3$ mole of $M n_{2} O_{4}^{-}$ and $1/3$ mole of $M n O_{2}$

$2/3$ mole of $M n_{2} O_{4}^{-}$ and $1/3$ mole of $M n O_{2}$

Mn $O_{4}^{2 -}$ in neutral aqueous medium is disproportionate to
$\frac{2}{3}$ mole of $M n O_{4}^{-}$ and $\frac{1}{3}$ mole of $M n O_{2}$ .

Q. MnO42−​ (1 mole) in neutral aqueous medium is disproportionate to

2/3mole of MnO4−​ and 1/3 mole of MnO2​

1/3mole of MnO4−​ and 2/3 mole of MnO2​

1/3mole of Mn2​O4−​ and 1/3 mole of MnO2​

2/3mole of Mn2​O4−​ and 1/3 mole of MnO2​