Q.
Minimum light intensity that can be perceived by normal human eye is about 10−10Wbm−2 . What is the minimum number of photons of wavelength 660nm that must enter the pupil in 1s for one to see the object? Area of cross-section of the pupil is 10−4m2 .
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Punjab PMETPunjab PMET 2010Dual Nature of Radiation and Matter
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Solution:
Intensity, I = 10−10Wbm−2=10−10Js−1m−2 .
Let the number of- photons required be n.
Then, 10−4nhv=10−10
Hence, n=10−10×10−4/hv =10−14hcλ =6.6×10−34×3×10810−14×660×10−9 =3.3×104