Millimoles of calcium hydroxide required to produce 100 mL of the aqueous solution of pH 12 is x × 10-1. The value of x is (Nearest integer). Assume complete dissociation.

Question

Millimoles of calcium hydroxide required to produce 100 mL of the aqueous solution of pH 12 is x × 10-1. The value of x is (Nearest integer). Assume complete dissociation. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

∵ pH =12 ∴[ H +]=10-12 M ∴[ OH ]=10-2 M ∴[ Ca ( OH )2]=5 × 10-3 M 5 × 10-3=( text milli moles of Ca ( OH )2/100 mL ) text milli moles of Ca ( OH )2=5 × 10-1 text Ans. =5

Q. Millimoles of calcium hydroxide required to produce $100 m L$ of the aqueous solution of $p H 12$ is $x \times 1 0^{- 1}$ . The value of $x$ is ___(Nearest integer). Assume complete dissociation.

$∵ p H = 12$
$∴ [H^{+}] = 1 0^{- 12} M$
$∴ [O H] = 1 0^{- 2} M$
$∴ [C a (O H)_{2}] = 5 \times 1 0^{- 3} M$
$5 \times 1 0^{- 3} = \frac{milli moles of C a ( O H ) _{2}}{100 m L}$
$milli moles of C a (O H)_{2} = 5 \times 1 0^{- 1}$
$Ans. = 5$

Q. Millimoles of calcium hydroxide required to produce 100mL of the aqueous solution of pH12 is x×10−1. The value of x is ___(Nearest integer). Assume complete dissociation.

∵pH=12 ∴[H+]=10−12M ∴[OH]=10−2M ∴[Ca(OH)2​]=5×10−3M 5×10−3=100mL milli moles of Ca(OH)2​​ milli moles of Ca(OH)2​=5×10−1 Ans. =5

Q. Millimoles of calcium hydroxide required to produce $100 m L$ of the aqueous solution of $p H 12$ is $x \times 1 0^{- 1}$ . The value of $x$ is ___(Nearest integer). Assume complete dissociation.

$∵ p H = 12$
$∴ [H^{+}] = 1 0^{- 12} M$
$∴ [O H] = 1 0^{- 2} M$
$∴ [C a (O H)_{2}] = 5 \times 1 0^{- 3} M$
$5 \times 1 0^{- 3} = \frac{milli moles of C a ( O H ) _{2}}{100 m L}$
$milli moles of C a (O H)_{2} = 5 \times 1 0^{- 1}$
$Ans. = 5$