Mg(.s.)|.Mg2 +(.aq.)|.|.Zn2 +(.aq.)|.Zn(.s.);E° =+3.13 textV The correct plot of Ec e l l versus log ([. M g2 + ]./[. Z n2 + ].) will be represented as

Question

Mg(.s.)|.Mg2 +(.aq.)|.|.Zn2 +(.aq.)|.Zn(.s.);E° =+3.13 textV The correct plot of Ec e l l versus log ([. M g2 + ]./[. Z n2 + ].) will be represented as (A) Option 1

(B)

(C)

(D)

Tardigrade Admin · Accepted Answer

For the given cell, E = E o -(0.059/2) log 10 ([ Mg 2+]/[ Zn 2+]) This equation is of the form y = mx + c, its slope is negative and intercept equal to E ° Slope =-(0.059/2) Intercept = E °.

Q. $M g (s) ∣ M g^{2 +} (a q) ∣ ∣ Z n^{2 +} (a q) ∣ Z n (s); E^{\circ} = + 3.13 V$
The correct plot of $E_{ce ll}$ versus $l o g \frac{[ M g ^{2 +} ]}{[ Z n ^{2 +} ]}$ will be represented as

For the given cell,
$E = E^{o} - \frac{0.059}{2} lo g_{10} \frac{[ M g ^{2 +} ]}{[ Z n ^{2 +} ]}$
This equation is of the form $y = m x + c$ , its slope is negative and intercept equal to $E^{\circ}$
Slope $= - \frac{0.059}{2}$
Intercept $= E^{\circ}$ .

Q. Mg(s)∣Mg2+(aq)∣∣Zn2+(aq)∣Zn(s);E∘=+3.13V The correct plot of Ecell​ versus log[Zn2+][Mg2+]​ will be represented as

For the given cell, E=Eo−20.059​log10​[Zn2+][Mg2+]​ This equation is of the form y=mx+c, its slope is negative and intercept equal to E∘ Slope =−20.059​ Intercept =E∘.

Q. $M g (s) ∣ M g^{2 +} (a q) ∣ ∣ Z n^{2 +} (a q) ∣ Z n (s); E^{\circ} = + 3.13 V$
The correct plot of $E_{ce ll}$ versus $l o g \frac{[ M g ^{2 +} ]}{[ Z n ^{2 +} ]}$ will be represented as

For the given cell,
$E = E^{o} - \frac{0.059}{2} lo g_{10} \frac{[ M g ^{2 +} ]}{[ Z n ^{2 +} ]}$
This equation is of the form $y = m x + c$ , its slope is negative and intercept equal to $E^{\circ}$
Slope $= - \frac{0.059}{2}$
Intercept $= E^{\circ}$ .