Question

Methylation of $10g$ of benzene gave $9.2g$ of toluene. Calculate the percentage yield of toluene______.

Answer 1

Answer: 78

$\underset{\frac{10}{78}}{C_6{H}_6}+C{H}_{3}Cl\to \underset{\left(\frac{10}{78}\times 92\right)gm\Rightarrow }{C_6{H}_{5}C{H}_3+HCl}$
$\frac{A_y}{T_y}=\%$ yield $=\frac{9.2}{920}\times 78\times 100\Rightarrow 78\%$