Methyl n-propyl ketone on oxidation with K2Cr2O7 and H2SO4 give mainly

Question

Methyl n-propyl ketone on oxidation with K2Cr2O7 and H2SO4 give mainly (A)  CH3CH2COOH+CH3COOH  (B) CH3CH2CH2COOH+HCOOH  (C)  CH3COOH+HCOOH  (D) CH3CH2COOH+CO2+H2O

Tardigrade Admin · Accepted Answer

During oxidation of unsymmetrical ketones, i.e.,

n

-propyl methyl ketone, the keto group stays with the smaller alkyl group (Popoffs rule) i.e.,

C H_{3} C H_{2} COO H

and

C H_{3} COO H

are formed.

C H_{3} COC H_{2} C H_{2} C H_{3} [O] C H_{3} COO H

+ C H_{3} C H_{2} COO H

Q. Methyl $n$ -propyl ketone on oxidation with $K_{2} C r_{2} O_{7}$ and $H_{2} S O_{4}$ give mainly

$C H_{3} C H_{2} COO H + C H_{3} COO H$

$C H_{3} C H_{2} C H_{2} COO H + H COO H$

$C H_{3} COO H + H COO H$

$C H_{3} C H_{2} COO H + C O_{2} + H_{2} O$

During oxidation of unsymmetrical ketones, i.e., $n$ -propyl methyl ketone, the keto group stays with the smaller alkyl group (Popoffs rule) i.e.,
$C H_{3} C H_{2} COO H$ and $C H_{3} COO H$ are formed.
$C H_{3} COC H_{2} C H_{2} C H_{3} [O] C H_{3} COO H$
$+ C H_{3} C H_{2} COO H$

Q. Methyl n-propyl ketone on oxidation with K2​Cr2​O7​ and H2​SO4​ give mainly

CH3​CH2​COOH+CH3​COOH

CH3​CH2​CH2​COOH+HCOOH

CH3​COOH+HCOOH

CH3​CH2​COOH+CO2​+H2​O