Question

Methyl $n$-propyl ketone on oxidation with $ K_{2}Cr_{2}O_{7} $ and $ H_{2}SO_{4} $ give mainly

• A. $ CH_{3}CH_{2}COOH+CH_{3}COOH $
• B. $CH_{3}CH_{2}CH_{2}COOH+HCOOH $
• C. $ CH_{3}COOH+HCOOH $
• D. $CH_{3}CH_{2}COOH+CO_{2}+H_{2}O$

Answer 1

Answer: (A)

During oxidation of unsymmetrical ketones, i.e., $n$-propyl methyl ketone, the keto group stays with the smaller alkyl group (Popoffs rule) i.e.,
$ CH_{3}CH_{2}COOH $ and $ CH_{3}COOH $ are formed.
$ CH_{3}COCH_{2}CH_{2}CH_{3}\xrightarrow[{}]{[O]}CH_{3}COOH $
$ +CH_{3}CH_{2}COOH $