Tardigrade
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Tardigrade
Question
Physics
Mean free path of a gas molecule is
Q. Mean free path of a gas molecule is
2139
220
Kinetic Theory
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A
inversely proportional to number of molecules per unit volume
B
inversely proportional to diameter of the molecule
C
directly proportional to the square root of the absolute temperature
D
directly proportional to the pressure
Solution:
Mean free path,
λ
=
2
π
d
2
n
1
where,
n
=
Number of molecules per unit volume
d
=
Diameter of the molecules
As
P
V
=
k
B
NT
∴
n
=
V
N
=
k
B
T
P
∴
λ
=
2
π
d
2
P
k
B
T
where,
k
B
=
Boltzmann constant
P
=
Pressure of gas
T
=
Temperature of the gas