Maximum number of photons emitted by a bulb capable of producing monochromatic light of wavelength 550 nm is ..........., if 100 V and 1 A is supplied for one hour.

Question

Maximum number of photons emitted by a bulb capable of producing monochromatic light of wavelength 550 nm is ..........., if 100 V and 1 A is supplied for one hour. (A) 1 × 1024 (B) 5 × 1024 (C) 2 × 1024 (D) 5 × 1023

Tardigrade Admin · Accepted Answer

E =(h c/λ) E =((6.626 × 10-34 J s )(3.0 × 108)/550 × 10-9) E =0.036 × 10-17 J Each proton carries 0.036 × 10-17 J of energy. P= IV =1 A × 100 V P=100 W A 100 W source means that it outputs 100 J of energy every one hour. So, in one second, 100 × 3600 J of energy is liberated. Number of photons emitted = total energy output in one second/energy carried per photon n=(100 × 3600/0.036 × 10-17)=1 × 1024

Q. Maximum number of photons emitted by a bulb capable of producing monochromatic light of wavelength $550 nm$ is ..........., if $100 V$ and $1 A$ is supplied for one hour.

$1 \times 1 0^{24}$

$5 \times 1 0^{24}$

$2 \times 1 0^{24}$

$5 \times 1 0^{23}$

$6 \times 1 0^{24}$

Q. Maximum number of photons emitted by a bulb capable of producing monochromatic light of wavelength 550nm is ..........., if 100V and 1A is supplied for one hour.

1×1024

5×1024

2×1024

5×1023