Maximum kinetic energy of a photoelectric varies with the frequency (f) of the incident radiation as

Question

Maximum kinetic energy of a photoelectric varies with the frequency (f) of the incident radiation as (A) Option 1

(B)

(C)

(D)

Tardigrade Admin · Accepted Answer

From Einstein's photoelectric equation, we have Km a x=hf-φ0 .....(i) Here, φ0= work function of the surface = constant From Equation. (i), graph of Km a x v/sf is <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-z11qauudbo11ry30.jpg" />

Q. Maximum kinetic energy of a photoelectric varies with the frequency $(f)$ of the incident radiation as

From Einstein's photoelectric equation, we have
$K_{ma x} = h f - ϕ_{0}$ .....(i)
Here, $ϕ_{0} =$ work function of the surface
$=$ constant
From Equation. (i), graph of $K_{ma x} v / s f$ is

Q. Maximum kinetic energy of a photoelectric varies with the frequency (f) of the incident radiation as

From Einstein's photoelectric equation, we have Kmax​=hf−ϕ0​ .....(i) Here, ϕ0​= work function of the surface = constant From Equation. (i), graph of Kmax​v/sf is

Q. Maximum kinetic energy of a photoelectric varies with the frequency $(f)$ of the incident radiation as

From Einstein's photoelectric equation, we have
$K_{ma x} = h f - ϕ_{0}$ .....(i)
Here, $ϕ_{0} =$ work function of the surface
$=$ constant
From Equation. (i), graph of $K_{ma x} v / s f$ is