Question

Maximum amplitude of SHM so block A will not slip on block B, K = 100 N/m

• A. 2
• B. 4
• C. 6
• D. 8

Answer 1

Answer: (C)

$F=m{w}^{2}A=\mu mg$
$A=\frac{\mu g}{{\omega }^2}$
$\omega =\sqrt{\frac{K}{m}}$
$\omega =\sqrt{\frac{100}{1.5}}$
$A=6cm$