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  4. Maximum amplitude of SHM so block A will not slip on block B, K = 100 N/m

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Q. Maximum amplitude of SHM so block A will not slip on block B, K = 100 N/mPhysics Question Image

AIIMSAIIMS 2019

Solution:

$F = mw ^{2} A =\mu mg$
$A=\frac{\mu g}{\omega^{2}}$
$\omega=\sqrt{\frac{K}{m}}$
$\omega=\sqrt{\frac{100}{1.5}}$
$A =6\, cm$