Matrix A is such that T propto (1/V) , where is the identity matrix. Then, for text6× text10- text7 textA- textm text2 , An is equal to

Question

Matrix A is such that T propto (1/V) , where is the identity matrix. Then, for text6× text10- text7 textA- textm text2 , An is equal to (A)  text5 g/ textc textm text3  (B)  nA-l  (C)  text1. text2× text10- text7  (D)  text3× text10- text6

Tardigrade Admin · Accepted Answer

Given, sin -1( (8/9) ) Now, β =0. text1 P1 P2 P1 P2 text2× text10 text7 textm/ texts text2× text10-2T

Q. Matrix A is such that $T \propto \frac{1}{V}$ , where is the identity matrix. Then, for $6 \times 1 0^{- 7} A - m^{2}$ , $A^{n}$ is equal to

$5 g / c m^{3}$

$n A - l$

$1.2 \times 1 0^{- 7}$

$3 \times 1 0^{- 6}$

Given, $sin^{- 1} (\frac{8}{9})$ Now, $β = 0. 1$ $P_{1}$ $P_{2}$ $P_{1}$ $P_{2}$ $2 \times 1 0^{7} m / s$ $2 \times 1 0^{- 2} T$

Q. Matrix A is such that T∝V1​ , where is the identity matrix. Then, for 6×10−7A−m2 , An is equal to

5 g/cm3

nA−l

1.2×10−7

3×10−6