Question

Water droplets are coming from an open tap at a particular rate. The spacing between a droplet observed at $4^{\text{th }}$ second after its fall to the next droplet is $34.3m$. At what rate the droplets are coming from the tap ? (Take $g=9.8m/s^2$ )

• A. 3 drops / 2 seconds
• B. 2 drops / second
• C. 1 drop / second
• D. 1 drop / 7 seconds

Answer 1

Answer: (C)

In $4\sec .1^{\text{st }}$ drop will travel
$\Rightarrow \frac{1}{2}\times (9.8)\times (4{)}^2=78.4m$
$\therefore 2^{\text{nd }}$ drop would have travelled
$\Rightarrow 78.4-34.3=44.1m$.
Time for $2^{\text{nd }}$ drop
$\frac{1}{2}(9.8)t^2=44.1$
$t=3\sec$
$\therefore$ each drop have time gap of $1\sec$
$\therefore 1$ drop per $\sec$