Match the column I with column II and mark the appropriate choice. Column I Column II (A) H2(g)+Br2(g) → 2HBr(g) (i) Δ H = Δ U - 2RT (B) PCl5(g) → PCl3(g)+Cl2(g) (ii) Δ H = Δ U + 3RT (C) N2(g) → 3H2(g)+2NH3(g) (iii) Δ H = Δ U (D) 2N2O5(g) → 4NO2(g)+O2(g) (iv) Δ H = Δ U + RT

Question

Match the column I with column II and mark the appropriate choice. Column I Column II (A) H2(g)+Br2(g) → 2HBr(g) (i) Δ H = Δ U - 2RT (B) PCl5(g) → PCl3(g)+Cl2(g) (ii) Δ H = Δ U + 3RT (C) N2(g) → 3H2(g)+2NH3(g) (iii) Δ H = Δ U (D) 2N2O5(g) → 4NO2(g)+O2(g) (iv) Δ H = Δ U + RT (A) (A) → (iii), (B) → (i), (C) → (ii), (D) → (iv) (B) (A) → (iii), (B) → (iv), (C) → (i), (D) → (ii) (C) (A) → (ii), (B) → (i), (C) → (iv), (D) → (iii) (D) (A) → (iv), (B) → (ii), (C) → (i), (D) → (iii)

Tardigrade Admin · Accepted Answer

(A): Δ ng = 2-2 = 0; hence Δ H = Δ U (B): Δ ng = 2-1 = 1; hence Δ H = Δ U + RT (C): Δ ng = 2 - 4 = -2; hence Δ H = Δ U - 2RT (D): Δ ng = 5 - 2 = 3; hence Δ H = Δ U + 3RT

$(A) \to (iii)$ , $(B) \to (i)$ , $(C) \to (ii)$ , $(D) \to (i v)$

$(A) \to (iii)$ , $(B) \to (i v)$ , $(C) \to (i)$ , $(D) \to (ii)$

$(A) \to (ii)$ , $(B) \to (i)$ , $(C) \to (i v)$ , $(D) \to (iii)$

$(A) \to (i v)$ , $(B) \to (ii)$ , $(C) \to (i)$ , $(D) \to (iii)$

$(A) : Δ n_{g} = 2 - 2 = 0$ ; hence $Δ H = Δ U$
$(B) : Δ n_{g} = 2 - 1 = 1$ ; hence $Δ H = Δ U + RT$
$(C) : Δ n_{g} = 2 - 4 = - 2$ ; hence $Δ H = Δ U - 2 RT$
$(D) : Δ n_{g} = 5 - 2 = 3$ ; hence $Δ H = Δ U + 3 RT$

Column I		Column II
(A)	$H_{2 (g)} + B r_{2 (g)} \to 2 H B r_{(g)}$	(i)	$Δ H = Δ U - 2 RT$
(B)	$PC l_{5 (g)} \to PC l_{3 (g)} + C l_{2 (g)}$	(ii)	$Δ H = Δ U + 3 RT$
(C)	$N_{2 (g)} \to 3 H_{2 (g)} + 2 N H_{3 (g)}$	(iii)	$Δ H = Δ U$
(D)	$2 N_{2} O_{5 (g)} \to 4 N O_{2 (g)} + O_{2 (g)}$	(iv)	$Δ H = Δ U + RT$

(A)→(iii), (B)→(i), (C)→(ii), (D)→(iv)

(A)→(iii), (B)→(iv), (C)→(i), (D)→(ii)

(A)→(ii), (B)→(i), (C)→(iv), (D)→(iii)

(A)→(iv), (B)→(ii), (C)→(i), (D)→(iii)

(A):Δng​=2−2=0; hence ΔH=ΔU (B):Δng​=2−1=1; hence ΔH=ΔU+RT (C):Δng​=2−4=−2; hence ΔH=ΔU−2RT (D):Δng​=5−2=3; hence ΔH=ΔU+3RT

$(A) \to (iii)$ , $(B) \to (i)$ , $(C) \to (ii)$ , $(D) \to (i v)$

$(A) \to (iii)$ , $(B) \to (i v)$ , $(C) \to (i)$ , $(D) \to (ii)$

$(A) \to (ii)$ , $(B) \to (i)$ , $(C) \to (i v)$ , $(D) \to (iii)$

$(A) \to (i v)$ , $(B) \to (ii)$ , $(C) \to (i)$ , $(D) \to (iii)$

$(A) : Δ n_{g} = 2 - 2 = 0$ ; hence $Δ H = Δ U$
$(B) : Δ n_{g} = 2 - 1 = 1$ ; hence $Δ H = Δ U + RT$
$(C) : Δ n_{g} = 2 - 4 = - 2$ ; hence $Δ H = Δ U - 2 RT$
$(D) : Δ n_{g} = 5 - 2 = 3$ ; hence $Δ H = Δ U + 3 RT$