Question

Match Column I with Column II:

Column I		Column II
A	Dielectric ring uniformly charged.	P	Time independent electrostatic field out of system.
B	Dielectric ring uniformly charged rotating with angular velocity $\omega$.	Q	Magnetic field.
C	Constant current in ring $i_0$.	R	Induced electric field.
D	$i=i_0\cos \omega t$	S	Magnetic moment.

• A. $(A)\to (P);(B)\to (Q),(S);(C)\to (Q),(S);(D)\to (P)$
• B. $(A)\to (P);(B)\to (Q),(S);(C)\to (Q),(S);(D)\to (Q),(S)$
• C. $(A)\to (P);(B)\to (Q),(S);(C)\to (Q),(S);(D)\to (Q),(R)(S)$
• D. $(A)\to (P);(B)\to (Q),(S);(C)\to (Q),(S);(D)\to (R),(S)$

Answer 1

Answer: (C)

$(A)\to (P)$
$E=\frac{kqx}{{\left(a^2+x^2\right)}^{\frac{3}{2}}}$

(B) $\to (Q),(S)$
A rotating (accelerated) charge creates a magnetic field. There is also a magnetic movement, namely, $\vec{m}=i\vec{A}$ associated with it.
$(C)\to (Q),(S)$

$\frac{{\mu }_{0}i{a}^2}{2{\left(a^2+x^2\right)}^{\frac{3}{2}}}$
$\vec{m}=i_0\vec{A}$
$(D)\to (Q),(R),(S)$
Time-varying current creates a time-varying field. Hence, the magnetic flux also varies with time, which creates induced emf (induced $\vec{E}$ ) in accordance with Faraday's law.