Mass of thin long metal rod is 2 kg and its moment of inertia about an axis perpendicular to the Iength of rod and passing through its one end is 0.5kg m2. Its radius of gyration is

Question

Mass of thin long metal rod is 2 kg and its moment of inertia about an axis perpendicular to the Iength of rod and passing through its one end is 0.5kg m2. Its radius of gyration is (A) 20 cm (B) 40 cm (C) 50 cm (D) 1 m

Tardigrade Admin · Accepted Answer

I=(mL2/3)=0.5 kg m2 ∴ K=(L/√3)

Q. Mass of thin long metal rod is 2 kg and its moment of inertia about an axis perpendicular to the Iength of rod and passing through its one end is $0.5 k g m^{2} .$ Its radius of gyration is

20 cm

40 cm

50 cm

1 m

$I = \frac{m L ^{2}}{3} = 0.5 k g m^{2}$
$∴ K = \frac{L}{3}$

Q. Mass of thin long metal rod is 2 kg and its moment of inertia about an axis perpendicular to the Iength of rod and passing through its one end is 0.5kgm2. Its radius of gyration is

20 cm

40 cm

50 cm

1 m

I=3mL2​=0.5kgm2 ∴K=3​L​

Q. Mass of thin long metal rod is 2 kg and its moment of inertia about an axis perpendicular to the Iength of rod and passing through its one end is $0.5 k g m^{2} .$ Its radius of gyration is

$I = \frac{m L ^{2}}{3} = 0.5 k g m^{2}$
$∴ K = \frac{L}{3}$