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  4. Mass of thin long metal rod is 2 kg and its moment of inertia about an axis perpendicular to the Iength of rod and passing through its one end is 0.5kg m2. Its radius of gyration is

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Q. Mass of thin long metal rod is 2 kg and its moment of inertia about an axis perpendicular to the Iength of rod and passing through its one end is $0.5kg m^2.$ Its radius of gyration is

Solution:

$I=\frac{mL^2}{3}=0.5\,kg\,m^2$
$\therefore K=\frac{L}{\sqrt{3}}$