Mass of a particle is 400 times than that of an electron and charge is double that of an electron. The particle is accelerated by a potential difference of 5 V. If particle is initially at rest, then its final KE will be

Question

Mass of a particle is 400 times than that of an electron and charge is double that of an electron. The particle is accelerated by a potential difference of 5 V. If particle is initially at rest, then its final KE will be (A) 5 eV (B) 10 eV (C) 100 eV (D) 2000 eV

Tardigrade Admin · Accepted Answer

Change in KE = work done by electric field due to potential difference applied KE f- KE i=q V ⇒ KE f-0=q V or KE f=q V (q=2 e) ⇒ KE =2 e × 5=10 eV

Q. Mass of a particle is $400$ times than that of an electron and charge is double that of an electron. The particle is accelerated by a potential difference of $5 V$ . If particle is initially at rest, then its final KE will be

$5 e V$

$10 e V$

$100 e V$

$2000 e V$

Change in $K E =$ work done by electric field due to potential difference applied
$K E_{f} - K E_{i} = q V$
$\Rightarrow K E_{f} - 0 = q V$
or $K E_{f} = q V (q = 2 e)$
$\Rightarrow K E = 2 e \times 5 = 10 e V$

Q. Mass of a particle is 400 times than that of an electron and charge is double that of an electron. The particle is accelerated by a potential difference of 5V. If particle is initially at rest, then its final KE will be

5eV

10eV

100eV

2000eV