Magnitude of magnetic field (in SI units) at the centre of a hexagonal shape coil of side 10 cm 50 turns and carrying current I (Ampere) in units of (μ0 I/π) is :

Question

Magnitude of magnetic field (in SI units) at the centre of a hexagonal shape coil of side 10 cm 50 turns and carrying current I (Ampere) in units of (μ0 I/π) is : (A) 250 √3 (B) 5 √3 (C) 500 √3 (D) 50 √3

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/0bfcf960f164c7f7735388faaf84cb1b-.png" /> B =(6 μ0 I/4 π a cos 30°) × 2 sin 30° × 50 =(μ0 I/π) (150/√3 a)=(50 √3/0.1) (μ0 I/π) =500 √3 (μ0 I/π)

Q. Magnitude of magnetic field (in $S I$ units) at the centre of a hexagonal shape coil of side $10 c m$ $50$ turns and carrying current $I$ (Ampere) in units of $\frac{μ _{0} I}{π}$ is :

$2503$

$53$

$5003$

$503$

$B = \frac{6 μ _{0} I}{4 πa c o s 3 0 ^{\circ}} \times 2 sin 3 0^{\circ} \times 50$
$= \frac{μ _{0} I}{π} \frac{150}{3 a} = \frac{50 3}{0.1} \frac{μ _{0} I}{π}$
$= 5003 \frac{μ _{0} I}{π}$

Q. Magnitude of magnetic field (in SI units) at the centre of a hexagonal shape coil of side 10cm 50 turns and carrying current I (Ampere) in units of πμ0​I​ is :

2503​

53​

5003​

503​