Question

Magnetic moment $3.87B.M$. is given by
(At. nos. $Ni=28,Ti=22,Cr=24,Co=27)$

• A. $T{i}^{3+}$
• B. $C{o}^{2+}$
• C. $N{i}^{2+}$
• D. $C{r}^{2+}$

Answer 1

Answer: (B)

Magnetic moment $(\mu )=\sqrt{n(n+2)}$
$3.87B.M$. corresponds to $3$ unpaired electrons.
$C{r}^{2+}-3d^4,4$ unpaired electrons
$C{o}^{2+}-3d^7,3$ unpaired electrons
$N{i}^{2+}-3d^8,2$ unpaired electrons
$T{i}^{3+}-3d^1,1$ unpaired electron