Magnetic flux through a plane of area A placed in a uniform magnetic field B (as shown in figure) can be written as

Question

Magnetic flux through a plane of area A placed in a uniform magnetic field B (as shown in figure) can be written as (A) φB=B × A (B) φB= B × A (C) φB=B ⋅ A (D) φB= B ⋅ A

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Magnetic flux through a plane of area A placed in a uniform magnetic field B can be written as <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/f56420a8244f4f1b30ec1d8c10ec94f0-.png" /> φB= B ⋅ A =B A cos θ where, θ is angle between B and A.

Q. Magnetic flux through a plane of area $A$ placed in a uniform magnetic field $B$ (as shown in figure) can be written as

$ϕ_{B} = B \times A$

$ϕ_{B} = B \times A$

$ϕ_{B} = B \cdot A$

$ϕ_{B} = B \cdot A$

Magnetic flux through a plane of area $A$ placed in a uniform magnetic field $B$ can be written as

$ϕ_{B} = B \cdot A = B A cos θ$
where, $θ$ is angle between $B$ and $A$ .

Q. Magnetic flux through a plane of area A placed in a uniform magnetic field B (as shown in figure) can be written as

ϕB​=B×A

ϕB​=B×A

ϕB​=B⋅A

ϕB​=B⋅A

Magnetic flux through a plane of area A placed in a uniform magnetic field B can be written as ϕB​=B⋅A=BAcosθ where, θ is angle between B and A.

Q. Magnetic flux through a plane of area $A$ placed in a uniform magnetic field $B$ (as shown in figure) can be written as

$ϕ_{B} = B \times A$

$ϕ_{B} = B \times A$

$ϕ_{B} = B \cdot A$

$ϕ_{B} = B \cdot A$

Magnetic flux through a plane of area $A$ placed in a uniform magnetic field $B$ can be written as

$ϕ_{B} = B \cdot A = B A cos θ$
where, $θ$ is angle between $B$ and $A$ .