Magnetic flux through a coil of resistance 10 Ω is changed by Δφ in 0.1 s. The resulting current in the coil varies with time as shown in the figure. Then |Δφ| is equal to (in weber)

Question

Magnetic flux through a coil of resistance 10 Ω is changed by Δφ in 0.1 s. The resulting current in the coil varies with time as shown in the figure. Then |Δφ| is equal to (in weber) (A) 6 (B) 4 (C) 2 (D) 8

Tardigrade Admin · Accepted Answer

As e = (Δφ/Δ t) or Ri = (Δ φ /Δ t) (∵ e = Ri ) ⇒ Δ φ =R(i.Δ t) = R × area under i -1 graph = 10× (1/2)×4×0.1 = 2 weber

Q. Magnetic flux through a coil of resistance 10 $Ω$ is changed by $Δ ϕ$ in 0.1 s. The resulting current in the coil varies with time as shown in the figure. Then $∣ Δ ϕ ∣$ is equal to (in weber)

6

4

2

8

As $e = \frac{Δ ϕ}{Δ t}$ or $R i = \frac{Δ ϕ}{Δ t} (∵ e = R i)$
$\Rightarrow Δ ϕ = R (i .Δ t)$
$= R \times$ area under $i - 1$ graph
$= 10 \times \frac{1}{2} \times 4 \times 0.1 = 2$ weber

Q. Magnetic flux through a coil of resistance 10 Ω is changed by Δϕ in 0.1 s. The resulting current in the coil varies with time as shown in the figure. Then ∣Δϕ∣ is equal to (in weber)

6

4

2

8

As e=ΔtΔϕ​ or Ri=ΔtΔϕ​(∵e=Ri) ⇒Δϕ=R(i.Δt) =R× area under i−1 graph =10×21​×4×0.1=2 weber

Q. Magnetic flux through a coil of resistance 10 $Ω$ is changed by $Δ ϕ$ in 0.1 s. The resulting current in the coil varies with time as shown in the figure. Then $∣ Δ ϕ ∣$ is equal to (in weber)

As $e = \frac{Δ ϕ}{Δ t}$ or $R i = \frac{Δ ϕ}{Δ t} (∵ e = R i)$
$\Rightarrow Δ ϕ = R (i .Δ t)$
$= R \times$ area under $i - 1$ graph
$= 10 \times \frac{1}{2} \times 4 \times 0.1 = 2$ weber