Magnetic flux in a circuit containing a coil of resistance 2 Ω changes from 2.0 Wb to 10 Wb in 0.2 s. The charge passed through the coil in this time is :

Question

Magnetic flux in a circuit containing a coil of resistance 2 Ω changes from 2.0 Wb to 10 Wb in 0.2 s. The charge passed through the coil in this time is : (A) 0.8 C (B) 1.0 C (C) 5.0 C (D) 4.0 C

Tardigrade Admin · Accepted Answer

From Faradays law of electromagnetic induction,
the emf

(e)

induced is equal to rate of change of magnetic flux

(ϕ)

,
i.e.,

∣ e ∣ = \frac{d ϕ}{d t}

Also,

∣ e ∣ = I R

where

I

is current and

R

is resistance.

∴

I R = \frac{d ϕ}{d t}

\Rightarrow

I d t = \frac{d ϕ}{R}

Charge,

q = I d t = \frac{d ϕ}{R}

Given,

d ϕ = 10 - 2 = 8 Wb, R = 2 Ω

∴

q = \frac{8}{2} = 4 C

Q. Magnetic flux in a circuit containing a coil of resistance 2Ω changes from 2.0Wb to 10Wb in 0.2s. The charge passed through the coil in this time is :

0.8 C

1.0 C

5.0 C

4.0 C

From Faradays law of electromagnetic induction, the emf (e) induced is equal to rate of change of magnetic flux (ϕ) , i.e., ∣e∣=dtdϕ​ Also, ∣e∣=IR where I is current and R is resistance. ∴ IR=dtdϕ​ ⇒ Idt=Rdϕ​ Charge, q=Idt=Rdϕ​ Given, dϕ=10−2=8Wb,R=2Ω ∴ q=28​=4C

Q. Magnetic flux in a circuit containing a coil of resistance $2 Ω$ changes from $2.0 Wb$ to $10 Wb$ in $0.2 s$ . The charge passed through the coil in this time is :