Magnetic field in a plane electromagnetic wave is given by vecB = B0 sin (k x + ω t ) hatj T Expression for corresponding electric field will be: Where c is speed of light.

Question

Magnetic field in a plane electromagnetic wave is given by vecB = B0 sin (k x + ω t ) hatj T Expression for corresponding electric field will be: Where c is speed of light. (A)  vecE = B0 c sin (kx + ω t) hatk V/m (B)  vecE = (B0/ c) sin (kx + ω t) hatk V/m (C)  vecE = - B0 c sin (kx + ω t) hatk V/m (D)  vecE = B0 c sin (kx - ω t) hatk V/m

Tardigrade Admin · Accepted Answer

C = (E0/B0) E = CB0 = CB0 CB0 sin (kx + ω t) hatj

Q. Magnetic field in a plane electromagnetic wave is given by $B = B_{0} sin (k x + ω t) \hat{j} T$
Expression for corresponding electric field will be :
Where c is speed of light.

$E = B_{0} c sin (k x + ω t) \hat{k} V / m$

$E = \frac{B _{0}}{c} sin (k x + ω t) \hat{k} V / m$

$E = - B_{0} c sin (k x + ω t) \hat{k} V / m$

$E = B_{0} c sin (k x - ω t) \hat{k} V / m$

$C = \frac{E _{0}}{B _{0}}$
$E = C B_{0}$
$= C B_{0}$
$C B_{0} s in (k x + ω t) \hat{j}$

Q. Magnetic field in a plane electromagnetic wave is given by B=B0​sin(kx+ωt)j^​T Expression for corresponding electric field will be : Where c is speed of light.

E=B0​csin(kx+ωt)k^V/m

E=cB0​​sin(kx+ωt)k^V/m

E=−B0​csin(kx+ωt)k^V/m

E=B0​csin(kx−ωt)k^V/m