Question

Magnetic field in a plane electromagnetic wave is given by $\vec{B} = B_0 \, \sin (k x + \omega t ) \hat{j} T$
Expression for corresponding electric field will be :
Where c is speed of light.

• A. $\vec{E} = B_0 \, c \, \sin (kx + \omega t) \hat{k} V/m$
• B. $\vec{E} = \frac{B_0}{ c} \, \sin (kx + \omega t) \hat{k} V/m$
• C. $\vec{E} = - B_0 \, c \, \sin (kx + \omega t) \hat{k} V/m$
• D. $\vec{E} = B_0 \, c \, \sin (kx - \omega t) \hat{k} V/m$

Answer 1

Answer: (A)

$C = \frac{E_{0}}{B_{0}}$
$E = CB_{0}$
$= CB_{0}$
$CB_{0} \,sin \left(kx + \omega t\right) \hat{j}$