Magnetic field due to a long solenoid of cross section 15cm is 200T . This solenoid crosses a square coil of area 2m at its center such that length of solenoid is parallel to the axis of coil then magnetic flux linked through the square coil is:-

Question

Magnetic field due to a long solenoid of cross section 15cm is 200T . This solenoid crosses a square coil of area 2m at its center such that length of solenoid is parallel to the axis of coil then magnetic flux linked through the square coil is:- (A) Zero (B) 0.1Wb (C) 0.2Wb (D) 0.3Wb

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-kyntrfic2dws3jb6.jpg" /> Magnetic field due to the solenoid is along its length so θ =0° φ=B.A. =200× 15× 10- 4 =0.3Wb

Q. Magnetic field due to a long solenoid of cross section $15 c m$ is $200 T$ . This solenoid crosses a square coil of area $2 m$ at its center such that length of solenoid is parallel to the axis of coil then magnetic flux linked through the square coil is:-

Zero

$0.1 Wb$

$0.2 Wb$

$0.3 Wb$

Magnetic field due to the solenoid is along its
length so $θ = 0^{\circ}$
$ϕ = B . A .$
$= 200 \times 15 \times 1 0^{- 4}$
$= 0.3 Wb$

Q. Magnetic field due to a long solenoid of cross section 15cm is 200T . This solenoid crosses a square coil of area 2m at its center such that length of solenoid is parallel to the axis of coil then magnetic flux linked through the square coil is:-

Zero

0.1Wb

0.2Wb

0.3Wb

Magnetic field due to the solenoid is along its length so θ=0∘ ϕ=B.A. =200×15×10−4 =0.3Wb

Q. Magnetic field due to a long solenoid of cross section $15 c m$ is $200 T$ . This solenoid crosses a square coil of area $2 m$ at its center such that length of solenoid is parallel to the axis of coil then magnetic flux linked through the square coil is:-

$0.1 Wb$

$0.2 Wb$

$0.3 Wb$

Magnetic field due to the solenoid is along its
length so $θ = 0^{\circ}$
$ϕ = B . A .$
$= 200 \times 15 \times 1 0^{- 4}$
$= 0.3 Wb$