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Q. Magnetic field due to a long solenoid of cross section $15cm$ is $200T$ . This solenoid crosses a square coil of area $2m$ at its center such that length of solenoid is parallel to the axis of coil then magnetic flux linked through the square coil is:-

NTA AbhyasNTA Abhyas 2020

Solution:

Solution
Magnetic field due to the solenoid is along its
length so $\theta =0^\circ $
$\phi=B.A.$
$=200\times 15\times 10^{- 4}$
$=0.3Wb$